2018 Oracle Challenger Series – Indian Wells – Women's Doubles

Taylor Townsend and Yanina Wickmayer won the title after defeating Jennifer Brady and Vania King 6–4, 6–4 in the final.

Indian Wells – Women's Doubles
2018 Oracle Challenger Series – Indian Wells
Champions	Taylor Townsend Yanina Wickmayer
Runners-up	Jennifer Brady Vania King
Final score	6–4, 6–4

This was the first edition of the tournament.

Seeds

Raluca Olaru / Olga Savchuk (First round)
Barbora Krejčíková / Vera Lapko (Semifinals)
Jennifer Brady / Vania King (Final)
Duan Yingying / Wang Yafan (Quarterfinals)

Draw

Key

Draw

	First Round							Quarterfinals							Semifinals							Final

	1	R Olaru O Savchuk	3	5
		S Chang A Mueller	6	7					S Chang A Mueller	1	1
		C Dolehide A Riske	6	6					C Dolehide A Riske	6	6
		N Broady E Hrdinová	3	3												C Dolehide A Riske	2	3
	3	J Brady V King	6	6											3	J Brady V King	6	6
		M Doi E Rodina	4	3				3	J Brady V King	6	6
		PC Gonçalves S Marand	6	6⁸	[1]			WC	J Elbaba I Neel	1	3
	WC	J Elbaba I Neel	3	7¹⁰	[10]																	3	J Brady V King	4	4
		V Golubic M Linette	1	3																			T Townsend Y Wickmayer	6	6
		T Townsend Y Wickmayer	6	6					T Townsend Y Wickmayer	6	6⁵	[10]
	Alt	S Kenin A Weinhold	1	6³				4	Y Duan Y Wang	4	7⁷	[6]
	4	Y Duan Y Wang	6	7⁷												T Townsend Y Wickmayer	6	6³	[10]
		A Tomljanović V Zvonareva	4	6	[5]										2	B Krejčíková V Lapko	2	7⁷	[6]
		A Petkovic F Schiavone	6	3	[10]				A Petkovic F Schiavone	3	4
		K Bondarenko V Lepchenko	0	0				2	B Krejčíková V Lapko	6	6
	2	B Krejčíková V Lapko	6	6

References

Main Draw

2018 WTA 125K series
Newport Beach (S, D) Indian Wells (S, D) Zhengzhou (S, D) Anning (S, D) Bol (S, D) Chicago (S, D) Mumbai (S, D) Limoges (S, D) Taipei (S, D) Houston (S, D)

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