2019 BNP Paribas Primrose Bordeaux – Doubles

Doubles
	2019 BNP Paribas Primrose Bordeaux
Champions	Grégoire Barrère; Quentin Halys
Runners-up	Romain Arneodo; Hugo Nys
Final score	6–4, 6–1

Bradley Klahn and Peter Polansky were the defending champions but chose not to defend their title.[1]

Grégoire Barrère and Quentin Halys won the title after defeating Romain Arneodo and Hugo Nys 6–4, 6–1 in the final.

Seeds

First Round					Quarterfinals					Semifinals				Final

1	N Mahut J Melzer	6⁴	6	[10]
	G Mager A Pellegrino	7⁷	4	[8]	1	N Mahut J Melzer	6³	2
WC	E Benchetrit T Lamasine	6	6		WC	E Benchetrit T Lamasine	7⁷	1^r
	D Gimeno Traver D Marrero	3	2							WC	E Benchetrit T Lamasine	3	1
4	S Gillé D Vega Hernández	6	6								R Arneodo H Nys	6	6
WC	G Jacq A Olivetti	4	2		4	S Gillé D Vega Hernández	6²	6	[4]
	R Arneodo H Nys	6	7⁷			R Arneodo H Nys	7⁷	4	[10]
	J Eysseric A Šančić	3	6³												R Arneodo H Nys	4	1
	E Ymer M Ymer	2	6	[10]											G Barrère Q Halys	6	6
ITF	Raúl Brancaccio K-M Maamoun	6	3	[6]		E Ymer M Ymer	2	4
ITF	Sergio Martos Gornés O Roca Batalla	3	7⁷	[6]	3	M Gong Ze Zhang	6	6
3	M Gong Ze Zhang	6	6⁴	[10]						3	M Gong Ze Zhang	4	3
	K Coppejans Z Kolář	6⁶	4								G Barrère Q Halys	6	6
	G Barrère Q Halys	7⁸	6			G Barrère Q Halys	7	6
WC	Joffrey de Schepper K de Schepper	2	3		2	J Cerretani N Monroe	5	4
2	J Cerretani N Monroe	6	6

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